We can choose at random between two options, between a hundred, between a million. But when we want all positive integers to have exactly the same chance, randomness breaks.

The Lottery Without Enough Randomness

Riddle statement

You want to design a perfectly fair lottery for choosing a positive integer:

1,\ 2,\ 3,\ 4,\dots

The condition is that every number must have exactly the same probability of being chosen.

Is this possible?

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Solution

No, it is not possible.

Suppose every number has the same probability.

Call that probability $p$.

Then:

the number 1 has probability $p$; the number 2 has probability $p$; the number 3 has probability $p$; and so on.

The sum of all probabilities should be 1, because some number must be chosen.

But there are two cases.

If:

$ p>0 $

then adding $p$ infinitely many times makes the sum grow without bound. It cannot equal 1.

If:

$ p=0 $

then every number has probability 0, and the total sum would also be 0. That cannot equal 1 either.

There is no third option.

Therefore, there is no uniform lottery over all positive integers.

Answer: no such lottery can be designed.